Question

Add the additive inverse of (-11)/5 and the multiplicative inverse of 15/7

Answer 1

SOLUTION

TO DETERMINE

Add the additive inverse of (-11)/5 and the multiplicative inverse of 15/7

EVALUATION

We have to add the additive inverse of (-11)/5 and the multiplicative inverse of 15/7

Here

$\displaystyle \sf{Additive \: inverse \: of \: - \frac{11}{5} \: \: is \: \: \frac{11}{5} }$

$\displaystyle \sf{Multiplicative \: inverse \: of \: \: \frac{15}{7} \: \: is \: \: \frac{7}{15} }$

Hence the required addition

$\displaystyle \sf{ = \frac{11}{5} + \frac{7}{15} }$

$\displaystyle \sf{ = \frac{33 + 7}{15} }$

$\displaystyle \sf{ = \frac{40}{15} }$

$\displaystyle \sf{ = \frac{8}{3} }$

FINAL ANSWER

The required answer

$\displaystyle \sf{ = \frac{8}{3} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. 18 thousand crore divided by 9 crore

https://brainly.in/question/31888056

2. Prove that the inverse of the product of two elements of a group is the product of the inverses taken in the reverse order

https://brainly.in/question/22739109

Answer 2

Answer

• Additive inverse of a number "x" is -x

So, Additive Inverse of -11/5 = -(-11/5) = 11/5

• Multiplicative is basically a reciprocal which means multiplicative inverse of a number "x" will be 1/x

So, Multiplicative Inverse of 15/7 = 7/15

Now, We are asked to Add Additive Inverse of -11/5 with Multiplicative Inverse of 15/7

⇒ 11/5 + 7/15

⇒ 33/15 + 7/15

⇒ 40/15

⇒ (5 × 8)/(5 × 3)

⇒ 8/3

_____________________________________

I suggest you to even see answer of amitnrw sir here : https://brainly.in/question/17387867

• You can get some useful hints