Math, asked by Dhriti363, 8 months ago

Add the additive inverse of ( -12 + 16 - 42 +3 of 7 ) to the multiplicative
Inverse of he product of 2, 3, 4

Answers

Answered by kvkeerthana

Sum of the additive inverse of ( -12 + 16 - 42 +3 of 7 ) to the multiplicative

inverse of he product of 2, 3, 4 is 673/24

Additive inverse of -12 is 12

Additive inverse of 16 is -16

Additive inverse of -42 is 42

Additive inverse of 3 is -3

Additive inverse of 7 is -7

12 - 16 + 42 - 3 -7

= 54 - 26

= 28

Multiplicative inverse of 2 is 1/2

Multiplicative inverse of 3 is 1/3

Multiplicative inverse of 4 is 1/4

1/2 × 1/3 × 1/4 = 1/24

Sum = 28 + 1/24

= 672/24 + 1/24

= 673/24

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