Add the additive inverse of ( -12 + 16 - 42 +3 of 7 ) to the multiplicative
Inverse of he product of 2, 3, 4
Answers
Answered by
0
Answer:
Sum of the additive inverse of ( -12 + 16 - 42 +3 of 7 ) to the multiplicative
inverse of he product of 2, 3, 4 is 673/24
Step-by-step explanation:
Additive inverse of -12 is 12
Additive inverse of 16 is -16
Additive inverse of -42 is 42
Additive inverse of 3 is -3
Additive inverse of 7 is -7
12 - 16 + 42 - 3 -7
= 54 - 26
= 28
Multiplicative inverse of 2 is 1/2
Multiplicative inverse of 3 is 1/3
Multiplicative inverse of 4 is 1/4
1/2 × 1/3 × 1/4 = 1/24
Sum = 28 + 1/24
= 672/24 + 1/24
= 673/24
HOPE IT HELPS U!
MARK AS BRAINLIEST!
Attachments:
Similar questions