Math, asked by afrarsath143, 5 months ago

Add the expressions: (i) pq −1 and 3pq + 2 (ii) 8x + 3 and 1 − 7x​

Answers

Answered by sanjana8419
4

Answer:

(i) (pq -1) +(3pq +2) =4pq +1

(ii) (8x +3) + (1-7x) = x +4

Answered by Manmohan04
3

Given,

\[\begin{array}{l}\left( i \right)\left( {pq - 1} \right)\,and\,\left( {3pq + 2} \right)\\\left( {ii} \right)\left( {8x + 3} \right)\,and\,\left( {1 - 7x} \right)\end{array}\]

Solution,

Add the expressions:

\[\begin{array}{l}\left( i \right)\,\,\left( {pq - 1} \right)\,and\,\left( {3pq + 2} \right)\\ = \left( {pq - 1} \right) + \left( {3pq + 2} \right)\\ = 4pq + 1\end{array}\]

\[\begin{array}{l}\left( {ii} \right)\left( {8x + 3} \right)\,and\,\left( {1 - 7x} \right)\\ = \left( {8x + 3} \right) + \left( {1 - 7x} \right)\\ = x + 4\end{array}\]

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