Question

Add the following :-
1 upon 2 ax , 1 upon 2 ax ​

Answer 1

HELLO DEAR,

x/a + y/b = 2

ay + xb = 2ab----------( 1 )

ax - by = a² - b²---------( 2 )

from-----( 1 ) &-------( 2 )

multiply ( 1 ) by "a" ( 2 ) by "b"

abx + a²y = 2a²b

abx - b²y = ba² - b³

-------------------------------------------------

y(a² + b²) = 2a²b - ba² + b³

y(a² + b²) = a²b + b³

y(a² + b²) = b(a² + b²)

y = b [ put in -----( 1 )]

we get,

ay + xb = 2ab

a(b) + xb = 2ab

xb = 2ab - ab

x = ab/b

x = a

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Answer:

The value of x is 2/( a+b-ab)

Step-by-step explanation:

Given Data: a/(ax-1) + b/(bx-1) = a+b ; To find the value of x:

a/ax-1 + b/bx-1 = a+b

Step 1:

(abx - a +abx-b)/(ax-1)(bx-1) = a+b

2 a b x-a-b=(a+b)\left(a b x^{2}-a x-b x+1\right)

Step 2:

2 \mathrm{abx}-\mathrm{a}-\mathrm{b}=\mathrm{a}^{2} \mathrm{bx}^{2}-\mathrm{a}^{2} \mathrm{x}-\mathrm{abx}+\mathrm{a}+\mathrm{ab}^{2} \mathrm{x}^{2}-\mathrm{abx}-\mathrm{b}^{2} \mathrm{x}+\mathrm{b}

Step 3:

\left.\begin{array}{l}{x\left(2 a b-a^{2} b+a^{2}-a b^{2}+b^{2}\right)=2 a+2 b} \\ {x\left[(a+b)^{2}-a^{2} b-a b^{2}\right]=2 a+2}\end{array} \quad \text { (therefore, }(a+b)^{2}=a^{2}+b^{2}+2 a b\right)

Step 4:

x = 2(a+b)/(a+b)(a+b-ab) (cancelling a+b)

x = 2/( a+b-ab)