Question

add the following
2x^2y^2-3xy+4,5+7xy-3x^2y^2

Answer 1

Answer:

$Answer:</p><p></p><p>\huge{\underline{\underline{Given→}}}Given→</p><p></p><p>\sf\green{Length\:of\:rectangel=x+2\:units}Lengthofrectangel=x+2units</p><p></p><p>\sf\green{Breadth\:of\:rectangel=2x\:units}Breadthofrectangel=2xunits</p><p></p><p>\huge{\underline{\underline{To\:Find→}}}ToFind→</p><p></p><p>\sf\purple{Perimeter\:of\:the\:rectangle}Perimeteroftherectangle</p><p></p><p>\sf\color{purple}{Area\:of\:the\:rectangle}Areaoftherectangle</p><p></p><p>\huge{\underline{\underline{Answer→}}}Answer→</p><p></p><p>Perimeter:-</p><p></p><p>As perimeter =2(Lenght+Breadth)</p><p></p><p>\sf\blue{→P=2(l+b)}→P=2(l+b)</p><p></p><p>\sf\blue{→P=2(2x+x+2)}→P=2(2x+x+2)</p><p></p><p>\sf\blue{→P=4x+2x+4}→P=4x+2x+4</p><p></p><p>\sf\blue{→P=6x+4}→P=6x+4</p><p></p><p>\mathrm{\boxed{\boxed{\pink{→P=6x+4✔}}}}→P=6x+4✔</p><p></p><p>Area:-</p><p></p><p>As area =Length x Breadth</p><p></p><p>\sf\color{blue}{→Ar=l\times b}→Ar=l×b</p><p></p><p>\sf\color{blue}{→Ar=2x\times (x+2)}→Ar=2x×(x+2)</p><p></p><p>\sf\color{blue}{→Ar=2x(x+2)}→Ar=2x(x+2)</p><p></p><p>\sf\color{blue}{→Ar=2x^2+4x}→Ar=2x2+4x</p><p></p><p>{\boxed{\boxed{\pink{→Ar=2x^2+4x✔}}}}→Ar=2x2+4x✔</p><p></p><p>☞ Hence the Perimeter of the rectangle is 6x+4 units and it's area is \mathrm{2x^2+4x}2x2+4x units which is the required answer.</p><p></p><p>HOPE IT HELPS.</p><p></p><p>$