Question

Add the following :-
9x²-4x+5,-3x²+5x-3,4-3x​

Answer 1

Step-by-step explanation:

$( {9x}^{2} - 4x + 5) + ( { - 3x}^{2} + 5x - 3) + (4 - 3x) \\ = {9x}^{2} - 4x + 5 - {3x}^{2} + 5x - 3 + 4 - 3x \\ = {9x}^{2} - {3x}^{2} - 4x + 5x - 3x + 5 - 3 + 4 \\ = {6x}^{2} + x - 3x + 2 + 4 \\ = {6x}^{2} - 2x + 6$

Hence your answer is

${6x}^{2}-2x+6$

Answer 2

Answer:

See it so simple

Step-by-step explanation:

First take al x2at one side like this 9x2+(_3x2)then put the x one on one slde like this (_4x)+5x(_3x)then put the normal one in one side like this -3-4(+4)then do the sum of all ad the ans of x2 will be 6x2 and ans of x will be -2x and the ans of normal will be -3 and the ans is 6x2-2x-3