Add the following: (a) 3x2y, -5x2y,-x2y
(b) a+b-3, b+2a-1
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Answer:
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Step-by-step explanation:
Answer:
\begin{gathered}i) \: \: \: \: \: 3x2y + ( - 5x2y) + ( - x2y) \\ \\ = 6xy + ( - 10xy) + ( - 2xy) \\ \\ = 6xy - 10xy - 2xy \\ \\ = - 6xy \\ \\ \\ ii) \: \: \: \: \: \: a + b - 3 + (b + 2a - 1) \\ \\ = a + 2a + b + b - 3 - 1 \\ \\ = 3a + 2b - 4\end{gathered}
i)3x2y+(−5x2y)+(−x2y)
=6xy+(−10xy)+(−2xy)
=6xy−10xy−2xy
=−6xy
ii)a+b−3+(b+2a−1)
=a+2a+b+b−3−1
=3a+2b−4
THIS IS THE ANSWER TO UR QUESTION.....
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