Math, asked by Adarsh7th, 6 months ago

Add the following: (a) 3x2y, -5x2y,-x2y

(b) a+b-3, b+2a-1​

Answers

Answered by IIMidnightHunterII
28

Answer:

i) \:  \:  \:  \:  \: 3x2y + (  - 5x2y) + ( - x2y) \\  \\  = 6xy + ( - 10xy) + ( - 2xy) \\  \\  = 6xy - 10xy - 2xy \\  \\  =  - 6xy \\  \\  \\ ii) \:  \:  \:  \:  \:  \:  a + b - 3 + (b + 2a - 1) \\  \\  = a + 2a + b + b - 3 - 1 \\  \\  = 3a + 2b - 4

THIS IS THE ANSWER TO UR QUESTION.....

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Answered by brainlyherotodass
6

Step-by-step explanation:

Answer:

\begin{gathered}i) \: \: \: \: \: 3x2y + ( - 5x2y) + ( - x2y) \\ \\ = 6xy + ( - 10xy) + ( - 2xy) \\ \\ = 6xy - 10xy - 2xy \\ \\ = - 6xy \\ \\ \\ ii) \: \: \: \: \: \: a + b - 3 + (b + 2a - 1) \\ \\ = a + 2a + b + b - 3 - 1 \\ \\ = 3a + 2b - 4\end{gathered}

i)3x2y+(−5x2y)+(−x2y)

=6xy+(−10xy)+(−2xy)

=6xy−10xy−2xy

=−6xy

ii)a+b−3+(b+2a−1)

=a+2a+b+b−3−1

=3a+2b−4

THIS IS THE ANSWER TO UR QUESTION.....

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