Math, asked by manyag42009, 4 months ago

add the following expression
-x2 -3xy + 3y2 + 8 , 3x2 - 5y2 -3 + 4xy and -6xy+ 2x2 -2 +y2​

Answers

Answered by vyshnavimalla36
2

= (-x2 -3xy + 3y2 + 8 )+( 3x2 - 5y2 -3 + 4xy) +( -6xy+ 2x2 -2 +y2​ )

= -x2 -3xy +3y2 +8 +3x2 - 5y2 -3 +4xy  -6xy + 2x2 - 2 +y2

=-x2+3x2+2x2 -3xy-4xy-6xy +3y2 -5y2 +y2  +8-3-2

= 4x2-13xy-y2+3

Answered by paulayaaattramdanso
1

Answer:

4x -5xy + y² -14y + 7

Step-by-step explanation:

-x2 -3xy + 3y2 + 8 + 3x2 - 5y2 -3 + 4xy + -6xy+ 2x2 -2 +y2​

-2x -3xy + 6y + 8 + 6x -10y -3 +4xy + -6xy + 4 + 2y

-2x + 6x -3xy + 4xy -6xy + y² + 6y -10y + 8 + 6 -3 + 4 -2

4x -5xy + y² -14y + 7

Similar questions