add the following expressions : 4m²-7n²+5mn,3n²+5m²-2mn
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13
Answer:
= 4m² - 7n² + 5mn + 3n² + 5m² - 2mn
= 4m² + 5m² - 7n² + 3n² + 5mn - 2mn
= 9m² - 4n² + 3mn
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3
Answer:
In 1 L of petrol, distance coverd by car = 16 km. therefore, In 11/4 L of petrol, distance covered by car = 16 × 11/4 = 44 km. In 2 whole 3/4 L of petrol, car will cover distance of 44 km
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