Question

Add the following fractions : 3/8 + 6/4​

Answer 1

Given

• $\frac{3}{8}$ + $\frac{6}{4}$

To find

• We have to add the fractions.

Solution

$\frac{3}{8}$ +  $\frac{6}{4}$

• We know that if the denominators of two Fractions are unequal It's known as Unlike Fractions.

So, these numbers which have given to solve are like fractions.

Now let's solve:-

$\frac{3}{8}$ - $\frac{6}{4}$

We have to now find the LCM of 8 and 4 because they are denominators of the Fractions.

The LCM of 8 and 4 is 8

$\frac{3}{8} \times \frac{1}{1} = \frac{3}{8}$

$\frac{6}{4} \times \frac{2}{2} = \frac{12}{8}$

Now, we have to add the Fractions

$\frac{3}{8} + \frac{12}{8} = \frac{15}{8}$

So, the answer is

$\frac{15}{8}$

Answer 2

Answer:

The value of $\frac{3}{8} +\frac{6}{4}$ is $\frac{15}{8}$.

Step-by-step explanation:

As per data given in the question,

We have,

$\frac{3}{8} +\frac{6}{4}$

To find the sum of given rational numbers, we must first equalize their denominators by taking the LCM if they are not equal.

Reduce the fraction $\frac{6}{4}$ to the lowest terms by extracting and canceling out $2$,

$=>\frac{3}{8} +\frac{3}{2}$

So, the LCM of $8$ and $2$ is $8$.

Convert $\frac{3}{8}$ and $\frac{3}{2}$ to fractions with denominator $8$,

$=> \frac{3}{8}+\frac{12}{8}$

Now, both denominators are the same,

Therefore we take denominator as common and add the numerators,

$=> \frac{3+12}{8}$

$=> \frac{15}{8}$

Hence, the required solution is $\frac{15}{8}$.