Math, asked by rajmdiqbal4711, 10 months ago

add the following it's fast I mark you siksha year ​

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Answered by prabhasharma6161
0

hope it will be helpful

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Answered by ayush6884
1

 {x}^{2}  +  {y}^{2}  + 2xy + 3 {x}^{2}  +  {y}^{2}  - 4xy +  {x}^{2}  +  {y}^{2}  \\  {x}^{2}  +   {3x}^{2}  +  {x}^{2} +  {y}^{2}   +  {y}^{2}  +  {y}^{2}  + 2xy - 4xy \\ 5 {x}^{2}  +  {3y}^{2}  - 2xy

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