Question

Add the following:
ta) 7a2bc, - 3abc2,3a2bc, 2abc2​

Answer 1

Answer:

Given terms are 7a2bc , −3abc2 , 3a2bc , 2abc2

Required sum =7a2bc+(−3abc2)+(3a2bc)+(2abc2)

Rearranging and collecting like terms,

=7a2bc+3a2bc−3abc2+2abc2

=(7+3)a2bc+(−3+2)abc2

=10a2bc−abc2

Step-by-step explanation:

please give me a point amd please make me brainless I hope I can help you you have a good day

Answer 2

Answer:

9a 4bc

Step-by-step explanation:

7a2bc

-3a 2bc

+3a2bc

+2a2bc

-------------

9a4bc

hope this helps