Question

Add the following using coloum method 7a+ 5b- 3c + 6a- 2b+2c+ 5 a+ 4b- 4c

Answer 1

Answer ⤵️

(6a+4b−c+3)+(2b−3c+4)+(11b−7a+2c−1)+(2c−5a−6)

⇒ 6a+4b−c+3+2b−3c+4+11b−7a+2c−1+2c−5a−6

Now arranging and combining the like terms,

⇒ 6a−7a−5a+4b+2b+11b−c−3c+2c+2c+3+4−1−6

⇒ −6a+17b

∴ The sum of (6a+4b−c+3),(2b−3c+4),(11b−7a+2c−1) and (2c−5a−6) is (−6a+17b)