Question

add the product of (-16) and (-9) to the quotient of (-132)by 6 solve it step by step​

Answer 1

Answer:

Addition of the product of (-16) and (-9) to the quotient of (-132) which when divided by 6, is 122.

Step-by-step explanation:

The product of (-16) and (-9)

=(-16)\times(-9)=144=(−16)×(−9)=144

So, the product of (-16) and (-9) is 144.

The quotient of (-132) by 6

= \frac {(-132)}{6}= -22=

6

(−132)

=−22

The quotient of a number is determined by dividing the dividend by the given divisor.

By that, the quotient of (-132) is determined by dividing it by 6, and the quotient is -22.

∴ The sum of the product of (-16) and (-9) to the quotient of (-132) by 6

\begin{gathered}=144+(-22)=144-22\\\\=122\end{gathered}

=144+(−22)=144−22

=122

Thus, the addition of the products and the quotient of the given numbers will result in the number 122.

Answer 2

Step-by-step explanation:

-169×-9+(-132)/6=144-22

=122