Math, asked by konthamharshith6, 11 months ago

Add the product : x(x+y-r),y(x-y+r),z(x-y-z)

Answers

Answered by kaustubhpoondir
123

Here we have the expressions

x(x + y-r),y(x-y + r) and z(x-y-z)

Using the distributive law

x(x + y-r)= x² + xy - xr,

y(x-y + r)= xy - y²+ yr

and

z(x-y-z) = xz - yz - z²

Now we add these terms

(x² + xy - xr) + (xy - y² + yr) + (xz -yz - z²)

Answer = x²- y²- z² + 2xy-xr + yr + xz - yz

plz mark as brainliest if this helps.

Answered by anuradhakonapala1979
5

Answer:

it is a distributive law after adding all the identities we will get the answer

Similar questions