Add the product : x(x+y-r),y(x-y+r),z(x-y-z)
Answers
Answered by
123
Here we have the expressions
x(x + y-r),y(x-y + r) and z(x-y-z)
Using the distributive law
x(x + y-r)= x² + xy - xr,
y(x-y + r)= xy - y²+ yr
and
z(x-y-z) = xz - yz - z²
Now we add these terms
(x² + xy - xr) + (xy - y² + yr) + (xz -yz - z²)
Answer = x²- y²- z² + 2xy-xr + yr + xz - yz
plz mark as brainliest if this helps.
Answered by
5
Answer:
it is a distributive law after adding all the identities we will get the answer
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