Question

add the square and cube of the same no. The result obtained if divided by the particular no until we can further divide the result with the no .And the new result obtained is one greater than the actual no .Example like 2^2+2^3=4+8=12
Now 12÷2=6 6÷2=3 now we can't divide the no further with two. The new result obtained is greater than two by one​

Answer 1

Answer:

Step-by-step explanation:

Let us assume that lucky number is x.

Now, as ‘x’ is made 4 times of itself, it grows to ‘4x’ . (That’s Great)

Now ‘4x’ is added to the square of ‘x’, it results in ‘4x + x ^2’ (Wohh, that’s big)

Now, this is equal to 96.

Therefore,

4x + x^2 = 96

Writing it in proper quadratic form,

x^2 + 4x - 96 = 0

Solving by splitting the middle term,

x^2 + 12x - 8x -96 = 0

(x + 12) (x - 8) = 0

Therefore,

x = -12 or x = 8

Answer is -12 or 8

8.9k views · View 8 Upvoters