Question

add two consecutive natural numbers and find the number one less than this.
it's also an algebraic question so please answer it as fast as possible.
I will mark it as my brain full answer.........

Answer 1

The question is not very clear, still as per the statement the solution would be:

Let the two consecutive natural numbers be a & (a+1).

The sum of the numbers will be a + a + 1 = 2a + 1

Now the number one less than this will be (2a + 1) - 1 = 2a + 1 - 1 = 2a. i.e. twice the first number.

Therefore, the number one less than the sum of two consecutive natural numbers will be twice the sum of the smaller number.