# add two consicutive natural numbers and find the number, one less than this

## Answers

**Step-by-step explanation:**

Let the two consecutive natural numbers be a & (a+1). Now the number one less than this will be (2a + 1) - 1 = 2a + 1 - 1 = 2a. i.e. twice the first number. Therefore, the number one less than the sum of two consecutive natural numbers will be twice the sum of the smaller number.

**Answer:**

Twice

**Step-by-step explanation:**

Let the two consecutive natural numbers be = a

= (a+1)

The sum of the numbers will be a + a + 1 = 2a + 1

**Now,**

The number one less than this will be (2a + 1) - 1 = 2a + 1 - 1

= 2a.

**Therefore,** the number one less than the sum of two consecutive natural numbers will be twice the sum of the smaller number.