Question

Add: -x+2y,-y+3z,-z+4x,-(x+y+z)​

Answer 1

Given equations are,

$-x+2y,-y+3z,-z+4x,-(x+y+z)$

Adding all the equations we get

$-x+2y+(-y+3z)+(-z+4x)+(-(x+y+z))$

$-x+2y-y+3z-z+4x-x-y-z$

Writing the similar terms together

$-x+4x-x+2y-y-y+3z-z-z$

$-2x+4x+2y-2y+3z-2z$

$2x+z$

Therefore, after adding $-x+2y,-y+3z,-z+4x,-(x+y+z)$ is $2x+z$.

Answer 2

Answer:

$2x+z$

Step-by-step explanation:

• Given terms:

$-x+2y,-y+3z,-z+4x,-(x+y+z)$

• On adding the given terms, we get

$-x+2y-y+3z-z+4x-x-y-z$

$=2x+z$

Hence, the sum of $-x+2y,-y+3z,-z+4x,-(x+y+z)$ is $2x+z$.