Question

Add (x^2yz−4xy^2z+7), (4+8xy^2z+4x^2yz) and (−11+9x^2yz+3xy^2z).

Answer 1

Answer:

Add $(x^2yz-4xy^2z+7), (4+8xy^2z+4x^2yz)$and $(-11+9x^2yz+3xy^2z)$ we get $7 (2x^2yz + xy^2z)$

Step-by-step explanation:

$(x^2yz-4xy^2z+7)+ (4+8xy^2z+4x^2yz) +(-11+9x^2yz+3xy^2z)$

Remove brackets without changing sign

$= x^2yz-4xy^2z+7 + 4+8xy^2z+4x^2yz -11+9x^2yz+3xy^2z$

Rearrange the similar terms

$= x^2yz+4x^2yz +9x^2yz -4xy^2z +8xy^2z +3xy^2z +7 + 4 -11 \\= (1 + 4+ 9)x^2yz + (-4 +8 + 3)xy^2z + ( 7 + 4- 11)\\= 14x^2yz + 7xy^2z\\= 7 (2x^2yz + xy^2z)$