Question

Add x2 + y2 – 2xy, -2x2 – y2 – 2xy and 3x2 + y2 + xy

Answer 1

(x² + y² – 2xy) + (-2x² – y² – 2xy) + (3x² + y² + xy)

= x² + y² – 2xy - 2x² – y² – 2xy + 3x² + y² + xy

= (1 - 2 + 3)x² + (1 - 1 + 1)y² + (-2 - 2 + 1)xy

= 2x² + y² - 3xy

Answer 2

Answer:

First lets add the 1st and 2nd term :

x2 + y2 - 2xy - 2x2 - y2 - 2xy

-x2 - 4xy

Now lets add the 3rd one :

-x2 - 4xy + 3x2 + y2 + xy

2x2 - 3xy + y2

Ans : 2x2 - 3xy + y2

Step-by-step explanation: