Question

Adding 10.0 mL of a dilute solution of zinc nitrate to 246 mL of 2.00 M sodium sulfide produced 0.279 g of a precipitate.
a) How many grams of zinc(II) nitrate and sodium sulfide were consumed to produce this quantity of product?
b) How many grams of excess reagent remains unreacted in the original solutions?
c) What is the concentration of the nitrate ion in solution after the precipitation reaction, assuming no further reaction?

Answer 1

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Answer 2

ANSWER

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