Question

Addition
1+1
2+2
3+3
4+4
5+5
6+6
7+9​

Answer 1

Answer:

In the series S= {12+23+34+45+56+67+78+89 +…up to 99 terms}, what's the 99th ... + 123,456,789^9) is divided by 999,999? 1,636 Views · What is the remainder when 1^5+2^5+ 3^5…

Answer 2

Answer:

1+1  = 2

2+2  = 4

3+3  = 6

4+4  = 8

5+5  = 10

6+6  = 12

7+9​ = 16

Step-by-step explanation:

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