Addition of 3m (3-m) and 4m²-8m
Answers
Answer:
Question;-
Find the cost of fencing a rectangular field 62m long and 33m wide at Ruppes 16 per metre.
Note:-
☯️Needed well explained and quality answers
☯️No spam
☯️No copy
☯️Don't go against tge rules.
Step-by-step explanation:
Given: The length of rectangular field is 62m and breadth of rectangular field is 33m at 16 per metre.
⠀
Need to find: The cost of fencing a rectangular field.
⠀
⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀
⠀
We know that, if we are given with the length of rectangular field and breadth of rectangular field, we have the required formula, that is,
⠀
\sf{:\implies Perimeter_{(rectangle)} = 2(l + b)}:⟹Perimeter
(rectangle)
=2(l+b)
⠀
⠀⠀⠀⠀ Here l is the length of rectangle & b is the breadth of rectangle, And here in this question we have l = 62m & b = 33m.
⠀
By using the required formula and substituting all the given values in the formula, we get:
⠀
\begin{gathered}\sf{:\implies \mathcal{P}erimeter_{(rectangle)} = 2(62 + 33)} \\ \\ \\ \sf{:\implies \mathcal{P}erimeter_{(rectangle)} = 2(95)} \\ \\ \\ \sf:\implies \boxed{\purple{\frak{Perimeter_{(rectangle)} = 190}}}\end{gathered}
:⟹Perimeter
(rectangle)
=2(62+33)
:⟹Perimeter
(rectangle)
=2(95)
:⟹
Perimeter
(rectangle)
=190
⠀
Now,
⠀
The cost of fencing a rectangular field:
⠀
\begin{gathered}\sf{:\implies \mathcal{C}ost = 16 \times \mathcal{P}erimeter_{(rectangle)}} \\ \\ \\ \sf{:\implies \mathcal{C}ost = 16 \times190} \\ \\ \\ \sf:\implies \boxed{\pink{\frak{Cost = 3040}}}\end{gathered}
:⟹Cost=16×Perimeter
(rectangle)
:⟹Cost=16×190
:⟹
Cost=3040
⠀
\sf{\therefore \underline{The\: cost\: of\: fencing \:a\: rectangular\: field\: is\:\textsf{\textbf{Rs.3040}}}}∴
ThecostoffencingarectangularfieldisRs.3040
Step-by-step explanation:
9m - 9m² _________ (1)
4m²-8m _________(2)
9m-9m²+4m²-8m
9m-8m-9m²+4m²
-m-5m²
-5m²-m
-(5m²+m