addition of digits of 2 digit number is 5 if we interchange the digits the new number is 9 more than original number find original number
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1
Answer:
23
Step-by-step explanation:
let the digit at tens place be a and that in one's place be b
the number becomes 10a+b
given a + b = 5..........eqn 1
again by reversing the digit the new number will be
10b+a
as per question
(10b+a) - (10a+b) = 9
10b + a - 10a -b = 9
9b - 9a =9
b-a = 1........eqn 2
adding eqn 1 and 2, we have
2b=6
b=3
this gives a=5-3=2
the number is 10a+b
= 20+3
=23.
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