Question

Addition of five consecutive numbers is 270. Find out sum of the 1st and 4th Number.​

Answer 1

$\large{\green{\bold{\underline{Let:}}}}$

$\sf \: The \: five \: numbers \: be \: x, \: x+1, \: x+2, \: x+3 \: and \: x+4$

$\large{\red{\bold{\underline{Then:}}}}$

$\large{\orange{\bold{\underline{According \: To \: Question:}}}}$

$\rightarrow \sf \: x + (x+1) + (x+2) + (x+3) + (x+4) = 270 \\ \\ \rightarrow \sf \: x + x+1 + x+2 + x+3 + x+4 = 270 \\ \\ \rightarrow \sf \: 5x + 10 = 270 \\ \\ \rightarrow \sf \: 5x = 270 - 10 \\ \\ \rightarrow \sf \: 5x = 260 \\ \\ \rightarrow \sf \: x = \frac{ \cancel260}{ \cancel5} \\ \\ \rightarrow \sf \: x = 52$

$\large{\red{\bold{\underline{Then:}}}}$

$\sf \: Numbers \: are \: 52, \: 52+1, \: 52+2, \\ \sf \: 52+3 \: and \: 52+4.$

$\large{\blue{\bold{\underline{Finally:}}}}$

$\sf \: Five \: consecutive \: numbers \: are \: 52, \: 53, \: 54, \\ \sf \: 55 \: and \: 56.$

$\large{\pink{\bold{\underline{But:}}}}$

$\sf \: We \: need \: to \: find \: addition \: of \: 1st \\ \sf \: and \: 4th \: number.$

$\rightarrow \sf \: 52 + 55 \\ \rightarrow \sf \: 107$

$\large{\green{\bold{\underline{Hence:}}}}$

$\underline{ \underline{ \sf \: The \: required \: Answer \: is \: 107.}}$

Answer 2

Answer:

Explanation:

36 as follows:

x + x+1 = 71

x+ x = 70

2x = 70

x = 35

x+1 = 36