Question

Addition of five consecutive numbers is 270. Then calculate the sum of the 1st and 2nd Number.

Note:-
1. Full calculation is needed.

2. Best answer will be marked brainliest

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Answer 1

$\large{\green{\bold{\underline{Let:}}}}$

$\sf \: The \: five \: numbers \: be \: x, \: x+1, \: x+2, \: x+3 \: and \: x+4$

$\large{\red{\bold{\underline{Then:}}}}$

$\large{\orange{\bold{\underline{According \: To \: Question:}}}}$

$\rightarrow \sf \: x + (x+1) + (x+2) + (x+3) + (x+4) = 270 \\ \\ \rightarrow \sf \: x + x+1 + x+2 + x+3 + x+4 = 270 \\ \\ \rightarrow \sf \: 5x + 10 = 270 \\ \\ \rightarrow \sf \: 5x = 270 - 10 \\ \\ \rightarrow \sf \: 5x = 260 \\ \\ \rightarrow \sf \: x = \frac{ \cancel260}{ \cancel5} \\ \\ \rightarrow \sf \: x = 52$

$\large{\red{\bold{\underline{Then:}}}}$

$\sf \: Numbers \: are \: 52, \: 52+1, \: 52+2, \\ \sf \: 52+3 \: and \: 52+4.$

$\large{\blue{\bold{\underline{Finally:}}}}$

$\sf \: Five \: consecutive \: numbers \: are \: 52, \: 53, \: 54, \\ \sf \: 55 \: and \: 56.$

$\large{\pink{\bold{\underline{But:}}}}$

$\sf \: We \: need \: to \: find \: addition \: of \: 1st \\ \sf \: and \: 2nd \: number.$

$\rightarrow \sf \: 52 + 53 \\ \rightarrow \sf \: 105$

$\large{\green{\bold{\underline{Hence:}}}}$

$\underline{ \underline{ \sf \: The \: required \: Answer \: is \: 105.}}$

Answer 2

Explanation:

Addition of five consecutive numbers is 270. Assume that the five consecutive numbers are x, (x + 1), (x + 2), (x + 3) and (x + 4).

As per given condition,

→ x + x + 1 + x + 2 + x + 3 + x + 4 = 270

→ 5x + 10 = 270

→ 5x = 270 - 10

→ 5x = 260

→ x = 52

Therefore, the numbers are:

• x = 52 (First number)
• x + 1 = 52 + 1 = 53 (Second number)
• x + 2 = 52 + 2 = 54 (Third number)
• x + 3 = 52 + 3 = 55 (Fourth number)
• x + 4 = 52 + 4 = 56 (Fifth number)

Also said that we have to find the sum of the 1st and 2nd number.

Assume that the sum of first and second number is y.

→ First number + Second number = y

→ 52 + 53 = y

→ 105 = y

Hence, the sum of first and second consecutive number is 105.