Question

Addition of HBr to propene yields 2- bromopropane while in the presence of benzoyl peroxide the same reaction yields 1- bromopropane . explain and give mechanism.​

Answer 1

Answer:

1) when we react HBr with propene it gives 2- bromopropane due to MARKONIKOV RULE it states that when an unsymmetrical compound(propene) reacts with an unsymmetrical reagent(HBr) the reagent adds to the carbon which contains the least hydrogen

2) when this reaction takes place in the presence of peroxide the reagent attaches itself to the carbon that contains most no of Hydrogen this is known as the antimarkonikov rule

note: markonikov rule is only applicable on unsymmetrical alkenes