Question

Additional Mathematics​

Answer 1

By hit and trial, we get x = 1 as one of the solutions of the given equation.

So, it can be written as

x³ - 3x² - 33x + 35 = (x - 1)(x² - 2x - 35)

Now solving

x² - 2x - 35 = x² -7x + 5x - 35

= x(x - 7) + 5(x - 7)

= (x - 7)(x + 5)

So ultimately

x³ - 3x² - 33x + 35 = 0

or, (x - 1)(x - 7)(x + 5) = 0

=> Either x = 1, or x = 7, or x = (-5)

Hence, solutions of the given equation are (-5), 1 and 7

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