Adiameter of rollers 84 cm and length is 120cm it takes 500complete revolution to roll once over the playground to level find the area of all play ground in m square
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Radius of the roller (r) = 84/ 2 cm = 42 cm
Length of the roller (h) = 120 cm
Curved surface area of the roller = 2πrh
= 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2
∴ area covered by the roller in 1 revolution = 31680 cm2
∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2
= 15840000 cm
Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2 Ans.
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