Math, asked by shidhant41, 7 months ago

Adie is thrown once. Fond the probability of getting

a) A prime number
b) A number lying between 1 and 5
c) An odd number​

Answers

Answered by Anonymous
1

Possible numbers of events on throwing a dice = 6

Numbers on dice = 1,2,3,4,5 and 6 

(i) Prime numbers = 2, 3 and 5

Favourable number of events = 3

Probability that it will be a prime number = 3/6 = 1/2

(ii) Numbers lying between 2 and 6 = 3, 4 and 5

Favourable number of events = 3

Probability that a number between 2 and 6 = 3/6 = 1/2

(iii) Odd numbers = 1, 3 and 5

Favourable number of events = 3

Probability that it will be an odd number = 3/6 =1/2

Answered by adityarajfun
1

Answer:

a=b=c=0.5

Step-by-step explanation:

A die has 6 sides - 1,2,3,4,5,6

Prime numbers - 2,3,5

numbers lying between 1 and 5 = 2,3,4

odd numbers - 1,3,5

Probability= No.of favourable outcomes/ total no. of outcomes

a) P(prime) = 3/6= 1/2= 0.5

b) P(Between 1 and 5) = 3/6=1/2=0.5

c)P(odd)=3/6=1/3=0.5

Have a good day

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