Adil and Biren together can complete a task in 20 days. Biren and Chirag together can complete the same task in 50 days. Adil and Chirag together can complete the same task in 40 days. If the Same task was to be done by them alone, what would be the ratio of time taken by Adil alone to taken by Biren?
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16
Adil=A
Biren=B
Chirag=C
A+B=20 days=1/20
B+C=50 days=1/50
A+C=40 days=1/40
A+B+B+C+A+C=(1/20)+(1/50)+(1/40)
2(A+B+C)= 19/200
(A+B+C)=(19/200)1/2
A+B+C=19/100
A-
(A+B+C)-(BC)=(19/100-(1/50)
A=17/100=100/17 days
B-
(A+B+C)-(A+C)= (19/100)-(1/40
B =14/200=7/100=100/7 days
srilavanya:
Answer is 9:11
Answered by
2
+ B)'s 1 day's work = 120120
(B + C)'s 1 day's work = 130130
(C + A)'s 1 day's work = 140140
On adding,
2(A + B + C)'s 1 day's work
= 120+130+140120+130+140
= 6+4+31206+4+3120 = 1312013120
∴∴ (A + B + C)'s 1 day's work
= 1324013240
∴∴ A's 1 day's work
= 1324013240 - 130130 = 13−824013−8240
= 52405240 = 148148
C's 1 day's work
= 1324013240 - 120120 = 13−1224013−12240
= 12401240
= ∴∴ Required ratio = 48 : 240 or 1 : 5
please mark as a brainliest
(B + C)'s 1 day's work = 130130
(C + A)'s 1 day's work = 140140
On adding,
2(A + B + C)'s 1 day's work
= 120+130+140120+130+140
= 6+4+31206+4+3120 = 1312013120
∴∴ (A + B + C)'s 1 day's work
= 1324013240
∴∴ A's 1 day's work
= 1324013240 - 130130 = 13−824013−8240
= 52405240 = 148148
C's 1 day's work
= 1324013240 - 120120 = 13−1224013−12240
= 12401240
= ∴∴ Required ratio = 48 : 240 or 1 : 5
please mark as a brainliest
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