Question

Adil tells his dad that the ratio of their present ages is 8:3. After 10
years, their ages will be in the ratio of 2:1. How old is Adil's father
currently?
O 49 years
O 51 years
O 43 years
0 40 years​

Answer 1

Step-by-step explanation:

x:y=8:3

y=3x/8

ATP

(x+10):(y+10) =2:1

x+10= 2(3x/8 +10)

(x+10)4=3x+80

x=40

Answer 2

Answer:

Adil is 15 years old and his father is 40 years.

Step-by-step explanation:

Let,

Present ages :

Adil's dad = 8x

Adil = 3x

After 10 years,

Age of Adil's dad = 8x + 10

Age of Adil = 3x + 10

Also,

Their ages will be in the ratio of 2 : 1

So,

$\dfrac{8x \: + \: 10}{3x \: + \: 10} = \dfrac{2}{1}$

=> 1(8x + 10) = 2(3x + 10)

=> 8x + 10 = 6x + 20

=> 8x - 6x = 20 - 10

=> 2x = 10

=> x = 10/2

=> x = 5

★ Adil's present age :

=> 3 × 5

=> 15 years

★ Father's present age:

=> 4 × 5

=> 40 years

Therefore, Adil is 15 years old and his father is 40 years.