Question

aditi is 4 times as oldas her son .5 year ago her son was 1/7 of her age .what is aditiage now?​

Answer 1

Answer:

Aditi's present age is 40 years

Explanation:

Let "a" be Aditi's present age.

Let "s" be the present age of Aditi's son.

We are given that Aditi's is four times her son's age.

=> a = 4s

We are also given that 5 years ago, her son was 1/7 of Aditi's age.

Aditi's age five years ago = a - 5

Her son's age five years ago = s - 5

=> (s - 5) = 1/7*(a - 5)

=> 7*(s - 5) = (a - 5)

=> 7s - 35 = a - 5

=> 7s - a = 30

Substituting a = 4s, we get:

7s - 4s = 30

3s = 30

s = 10

a = 4s = 40

Aditi's present age is 40 years

Her son's present age is 10 years

Check:

1. Aditi is four times her son's age [ 40 = 4*10} √

2. Five years ago, her son was 1/7 his mother's age. Aditi was 35 years old, five years ago, and her son was 5. It can be seen that 5 is 1/7 of 35. √