Aditi is three year elder than diksha.six year ago, aditi's age was four times diksha's age.find the age of aditi and diksha
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let Aditi's age is equal to X years
let Deeksha's age= (x - 3)years
6 years ago Aditi's age = (X - 6 )years
6 years ago Deeksha 's age = (x - 9) years
ATQ,
x-6 =4(x-9)
x-6 =4x-36
30 =3x
10 =x
so Aditi's age =x =10 years
Deeksha's age=(x-3) =10 -3 =7 years
let Deeksha's age= (x - 3)years
6 years ago Aditi's age = (X - 6 )years
6 years ago Deeksha 's age = (x - 9) years
ATQ,
x-6 =4(x-9)
x-6 =4x-36
30 =3x
10 =x
so Aditi's age =x =10 years
Deeksha's age=(x-3) =10 -3 =7 years
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Answered by
1
Answer:
let Aditi's age is equal to X years
let Deeksha's age= (x - 3)years
6 years ago Aditi's age = (X - 6 )years
6 years ago Deeksha 's age = (x - 9) years
ATQ,
x-6 =4(x-9)
x-6 =4x-36
30 =3x
10 =x
so Aditi's age =x =10 years
Deeksha's age=(x-3) =10 -3 =7 years
Step-by-step explanation:
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