Question

Aditi runs a handicraft shop in Bapu bazaar in Jaipur. She makes beautiful necklaces using
colourful beads which she keeps in a bag. Today she prepared 19 necklaces but could not
make the 20th necklace as she had no yellow beads left. She counted the beads and found
that there were 8 red, 6 green and 14 blue beads remaining in her bag. Her little daughter
Dulari requested for a bead. Aditi decides to take out one bead from bag for Dulari.
Find the probability that she draws a green bead.
a)
11
b) c)
ii. Find the probability that the bead drawn by her is not green.
b);
d)
iii. Find the probability that she draws a yellow bead.
b b)
d) 0
iv. Find the probability that she draws a red bead.
b)
28
v. Find the probability of getting one blue bead.
a) 14
b) 28
d) 1
8
8
8
a)
8
C
20
19
48​

Answer 1

Step-by-step explanation:

p(green)=6/28=3/14

ii) p(not green)=22/28=11/14

iii)p(yellow)=0

iv)p(red)=8/28=2/7

v)p(blue)=14/28=1/2

Answer 2

Answer:

Step-by-step explanation:

idk