Question

Aditi runs a handicraft shop in Bapu bazar in Jaipur. She makes beautiful necklaces
using colourful beads which she keeps in a potli. Today she prepared 19 necklaces but
could not make the 20th necklace as she had no yellow beads left. She counted the
beads and found that there were 8 red, 6 green and 14 blue beads remaining in her
potli. Her little daughter Dulari requested for a bead. Aditi decides to take out one bead
from her potli for Dulari.

1) Find the probability that she draws a green bead.

2) Find the probability that the bead drawn by her is not green.

3) Find the probability that she draws either a green or a blue bead.

4) Find the probability that she draws neither a red nor a green bead. ​

Answer 1

Answer:

could not make the 20th necklace as she had no yellow beads left. She counted the

beads and found that there were 8 red, 6 green and 14 blue beads remaining in her

potli. Her little daughter Dulari requested for a bead. Aditi decides to take out one bead

from her potli for Dulari.

1) Find the probability that she draws a green bead.

2) Find the probability that the bead drawn by her is not green.

3) Find the probability that she draws either a green or a blue bead.

4) Find the probability

Answer 2

Answer: 3/14 is the probability of getting a green bead.

              11/14 is the probability of getting a bead that is not green

              5/7 is the probability of getting a bead that she draws a green                    

or a blue bead

              1/2 is the probability of getting a bead that is neither red nor green

Given: It is given that she has 8 red, 6 green and 14 blue beads in her potli.

To Find: We need to find the probability that

1. she draws a bead that is green
2. she draws a bead that is not green
3. she draws a bead that is either green or blue
4. she draws a bead that is neither red nor green in color

Step-by-Step Explanation: We will calculate the probability using the following formula:

P = $\frac{No. \ of \ favorable \ outcomes}{Total \ possible \ outcomes}$

Step 1: Probability of getting a green bead is:

P = $\frac{6}{28}$ = $\frac{3}{14}$

Step 2: Probability of getting a bead that is not green

P = $\frac{22}{28}$ = $\frac{11}{14}$

Step 3: Probability of getting a bead that is either green or blue

P = $\frac{20}{28}$ = $\frac{5}{7}$

Step 4: Probability of getting a bead that is neither red nor green

P = $\frac{14}{28}$ = $\frac{1}{2}$

To know more about the topic probability, refer to the links below:

https://brainly.in/question/4616145

https://brainly.in/question/7659821

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