Math, asked by vinklemittal1985, 4 days ago

Aditya has 48 bananas while kritika has 32 bananas. What is the per cent of:(a) number of bananas that Aditya has more over the number of bananas kritika has? (b) number of bananas that kritika has less over the number of bananas Aditya has? please solve step by step​

Answers

Answered by sreetanu1lucky
0

Answer:

b)Krittika has 8 bananas less than Aditya

Answered by mehakdeepfzr1
1

Answer: a: the percentage of bananas that aditya has more over the number of bananas kritika has is 50%.

b: the percentage of number of bananas that kritika has less over the number of bananas Aditya has is 33.333%.

Step-by-step explanation:

a): number of bananas that Aditya has more over number of bananas that kritika has = 48-32 i.e.,=16

To find the percentage of number of bananas that aditya has more over kritika will be 16÷32 because we have to find the percentage with respect to kritika.

Now, we have to find the percentage we will multiply it by 100. So,

16÷32×100 i.e., 50%.

Hence, the percentage of number of bananas that aditya has more over kritika is 50%.

b): number of bananas that kritika has less over the number of bananas aditya has will be = 48-32 i.e.,=16

Now , to find the percentage of number of bananas that kritika has less over aditya will be=16÷48 because we have to find the percentage with respect to aditya.

Now, to find percentage we will multiply it by 100. So,

16÷48×100= 33.333%

Hence, the percentage of number of bananas that kritika has less over number of bananas aditya has is 33.333%.

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