Math, asked by choudharypravin690, 4 days ago

Aditya sells his two cycle at the rate of 5hundred each on one cycle he gain 6% while on other cylcle he insures loss6% find his total lossgain in whole transaction​

Answers

Answered by kumarashwinvats
1

Answer:

His total loss in whole transaction = Rs 4

Step-by-step explanation:

Given that:

Aditya sells his two cycles at the rate of Rs. 500 each.

To Find:

His total loss/gain in whole transaction.

Formula used:

CP = (SP × 100)/(100 + Gain%)

CP = (SP × 100)/(100 - Loss%)

First finding the CP at gain of 6%:

→ CP = (SP × 100)/(100 + Gain%)

→ CP = Rs. (500 × 100)/(100 + 6)

→ CP = Rs. 50000/106

→ CP = Rs. 472 (approx.)

Now finding the CP at loss of 6%:

→ CP = (SP × 100)/(100 - loss%)

→ CP = Rs. (500 × 100)/(100 - 6)

→ CP = Rs. 50000/94

→ CP = Rs. 532 (approx.)

Total selling price = Rs (500 + 500)

Total selling price = Rs 1000

Total cost price = Rs (472 + 532)

Total cost price = Rs 1004

Here, Cost price is greater than the selling price.

So, Loss.

Loss = CP - SP

Loss = Rs (1004 - 1000)

Loss = Rs 4

Answered by 09616
0

Answer:

His total loss in whole transaction = Rs 4

Step-by-step explanation:

Given that:

Aditya sells his two cycles at the rate of Rs. 500 each.

To Find:

His total loss/gain in whole transaction.

Formula used:

CP = (SP × 100)/(100 + Gain%)

CP = (SP × 100)/(100 - Loss%)

First finding the CP at gain of 6%:

→ CP = (SP × 100)/(100 + Gain%)

→ CP = Rs. (500 × 100)/(100 + 6)

→ CP = Rs. 50000/106

→ CP = Rs. 472 (approx.)

Now finding the CP at loss of 6%:

→ CP = (SP × 100)/(100 - loss%)

→ CP = Rs. (500 × 100)/(100 - 6)

→ CP = Rs. 50000/94

→ CP = Rs. 532 (approx.)

Total selling price = Rs (500 + 500)

Total selling price = Rs 1000

Total cost price = Rs (472 + 532)

Total cost price = Rs 1004

Here, Cost price is greater than the selling price.

So, Loss.

Loss = CP - SP

Loss = Rs (1004 - 1000)

Loss = Rs 4

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