Math, asked by gaibalwadhon, 11 months ago

adius
F
ex
Using in
are (-1,0).(
Using integration
equations y = 2x + 1.
2.0) and rad!
2), we have
(x - 2)² + y = x
x - 4x + 4 + y = x + y
x= 1 which gives y = + V3
Thus, the points of intersection of the given
urcles are A(1, 3) and A'(1, - 13 ) as shown in
the Fig 8.19.
Page No.
(Date:
I
1201
Find area under the curve
the given egy
of the line to
zxt 2
Izt​

Answers

Answered by narsingrao754
1

Answer:

adius

F

ex

Using in

are (-1,0).(

Using integration

equations y = 2x + 1.

2.0) and rad!

2), we have

(x - 2)² + y = x

x - 4x + 4 + y = x + y

x= 1 which gives y = + V3

Thus, the points of intersection of the given

urcles are A(1, 3) and A'(1, - 13 ) as shown in

the Fig 8.19.

Page No.

(Date:

I

1201

Find area under the curve

the given egy

of the line to

zxt 2

Izt

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