Question

adjacent figure is triangular in shape and is semi circular at the bottom .find the total area of this figure

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Answer 1

Step-by-step explanation:

Consider triangle OAB,

By Pythagoras theorem,

OB^2 = AB^2 + OA^2

100 = 36 + OA^2

OA = 8

$area \: of \: triangle \: = \frac{1}{2} \times base \times height$

area of triangle OAB = 0.5 x 12 x 8

= 48 m^2

$area \: of \: triangle \: = \frac{\pi {r}^{2} }{2}$

area of semicircle = (22/7 x 36)/2

= 56.6 m^2

area of the figure = area of triangle + area of semicircle

= 48 + 56.6

= 104.6 m^2

Hopefully, it helps.