adjacent side of a parallelogram are in the ratio 3 ratio 8 and the perimeter is is 110 find the sides of parallelogram
Answers
Answered by
16
Given:
- Adjacent sides of a paralleogram are in ratio 3:8.
- Perimeter of paralleogram is 110 units .
To Find:
- The measure of sides of the paralleogram.
Answer:
Given that adjacent sides are in ratio 3:8.
Let us take the ratio be 3x:8x .
Some points about paralleogram:
- ☞Opposite sides are equal .
- ☞Opposite angles are equal.
- ☞Adjacent angles sum is 180°.
- ☞Diagonals bisect each other.
From properties of paralleogram its clear that the other two sides will be 3x and 8x .
=> Perimeter = 3x+3x+8x+8x .
=> Perimeter = 6x + 16x .
But it is given 110 units. So ,
Hence
- ☞Measure of first side = 3x = 3×5u=15 units.
- ☞Measure of second side = 8x=8×5u = 40 units.
- ☞Measure of third side = 3x = 3×5u=15units.
- ☞Measure of fourth side = 8x =8×5u = 40 units.
Attachments:
Answered by
10
GIVEN :-
- Adjacent sides of parallelogram are in the ratio 3:8
- Perimeter of Parallelogram is 110 unit
TO FIND :-
- The sides of parallelogram = ?
SOLUTION :-
Let, the ratio constant be x
Therefore, Adjacent sides be = 3x and 8x
▪︎perimeter of parallelogram = 110 unit
=> 2 (3x + 8x) = 110
=> 2 (11x) = 110
=> 22x = 110
=> x = 110/22
=> x = 5
Hence,
▪︎Side ,AD = 3x = 3 × 5 = 15 unit
AB = 8x = 8 × 5 = 40 unit
BC = 3x = 3 × 5 = 15 unit
CD = 8x = 8 × 5 = 40 unit
Similar questions
Chemistry,
4 months ago
English,
4 months ago
English,
4 months ago
Computer Science,
10 months ago
Computer Science,
10 months ago
Social Sciences,
1 year ago