Question

adjacent sides of a grassy field is in the shape of a parallelogram are 28m and 42m. one of its diagonals is 38m long..it is available to four horses to graze..how much area of grass field will each horse get??​

Answer 1

Step-by-step explanation:

Given adjacent sides of a grassy field is in the shape of a parallelogram are 28 m and 42 m. one of its diagonals is 38 m long..it is available to four horses to graze..how much area of grass field will each horse get??​

• Area of parallelogram MNOP = 2 x area of triangle NOP
• Now S = a + b + c / 2
•            = 28 + 42 + 38 / 2
•            = 108 / 2
•           = 54 m
• Area of triangle is given by = √s(s – a) (s – b) (s – c)
•                           = √54 (54 – 28) (54 – 42) (54 – 38)
•                           = √54 x 26 x 12 x 16
•                           = √269568
•                           = 144 √13
•                           = 519.12
•                           = 520 cm^2
• Now area of parallelogram PQRS = 2 x 520  
•     = 1040 cm^2
• Therefore for 4 horses to graze area is 1040 cm^2
• So for 1 horse to graze area will be 1040 / 4 = 260 cm^2