Question

Adjacent sides of a rectangle are 7cm and 24cm. Find the length of its diagonal

Answer 1

Here's the answer

Refer the attachment for the figure.

Let ABCD be a rectangle.

In ∆ABC ,

Angle B = 90°

$\sf { AC^2 = AB^2 + BC^2} ... Pythagoras \: theorem$

= $\sf { 7^2 + 24^2 }$

= 49 + 576

= 625

AC = √625

AC = 25 cm

The length of the diagonal is 25 cm.

Thanks!!

Answer 2

Answer:

Heya....

Here is your answer ----

In the given figure, ABCD is a rectangle with length 24 cm and breadth 7 cm.

Also, in the figure, BCD is a triangle right angled at D.

CD = Base = B = 24 cm

BD = Perpendicular = P = 7 cm

BC = Hypotenuse = H = H

So, according to Pythagoras Theorem,

Hypotenuse^2 = Base^2 + Perpendicular^2

(H)^2 = (B)^2 + (P)^2

=> (H)^2 = (24)^2 + (7)^2

=> (H)^2 = 576 + 49

=> (H)^2 = 625

=> H = √(625)

=> H = 25 cm

Diagonal = Hypotenuse = 25 cm

HOPE IT HELPS.....!!!