Adjacent sides of rectangle are in the ratio 5:12.If the perimeter of the rectangle is 34 cm,find the length of the diagonal.
Answers
Answered by
346
Heya !!!
Let sides of rectangle be 5X and 12X.
Perimeter of rectangle = 34
2 ( L + B ) = 34
2 ( 12X + 5X) = 34
17X = 17
X = 17/17 = 1 cm
Length of rectangle = 12X = 12 × 1 = 12 cm
And,
Breadth of rectangle = 5X = 5 × 1 = 5 cm
Therefore,
Length of diagonal = ✓(L)²+(B)²
=> ✓(12)² + (5)²
=> ✓144 + 25
=> ✓169
=> 13 cm
★ HOPE IT WILL HELP YOU ★
Let sides of rectangle be 5X and 12X.
Perimeter of rectangle = 34
2 ( L + B ) = 34
2 ( 12X + 5X) = 34
17X = 17
X = 17/17 = 1 cm
Length of rectangle = 12X = 12 × 1 = 12 cm
And,
Breadth of rectangle = 5X = 5 × 1 = 5 cm
Therefore,
Length of diagonal = ✓(L)²+(B)²
=> ✓(12)² + (5)²
=> ✓144 + 25
=> ✓169
=> 13 cm
★ HOPE IT WILL HELP YOU ★
jjjjjjjhj:
Thnxx a lot
Answered by
95
Hello!!
Here is the answer.
Given that adjacent sides are in ratio 5:12 and perimeter is 34 cm.
Let the common ratio be k.
So, sides will be 5k and 12k.
Now,
P = 2(sum of adjacent sides)
34 = 2 ( 12k + 5k)
34 = 2 (17k)
34 = 34k
k = 1.
So, sides are
12k = 12×1 = 12 cm and 5k = 5 cm.
Now, using Pythagoras theorem.
Diagonal² = base² + altitude²
D² = 12² + 5²
D² =144 + 25
D = √169 = 13 cm.
Hence, the diagonal is 13 cm in length.
Hope It Helps
Here is the answer.
Given that adjacent sides are in ratio 5:12 and perimeter is 34 cm.
Let the common ratio be k.
So, sides will be 5k and 12k.
Now,
P = 2(sum of adjacent sides)
34 = 2 ( 12k + 5k)
34 = 2 (17k)
34 = 34k
k = 1.
So, sides are
12k = 12×1 = 12 cm and 5k = 5 cm.
Now, using Pythagoras theorem.
Diagonal² = base² + altitude²
D² = 12² + 5²
D² =144 + 25
D = √169 = 13 cm.
Hence, the diagonal is 13 cm in length.
Hope It Helps
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