Question

adjoining figure if O is the centre of the circle and O Q R equal to 50 degree then angle Q P R is equal to

Answer 1

angle pqr=90° [angle in a semicircle is perpendicular]
in triangle oqr,

oq=or radius of one circle
angle oqr =-angle orq (angle opposite to equal sides of a triangle are equal)

in triangle pqr

angle p+ angle q + angle r = 180°
angle p + 90° + 50° = 180°
angle p + 140°= 180°
angle p = 180-140
angle p = 40°