adjoining figure shows the cross section of a concrete wall to be constructed it is 1.9 wide at the bottom 90 cm wide at the top and 5 metre if its length is 20 find the cross sectional area and the volume of the concrete in the wall??
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Answers
Area of the structure is 7 m2 ; while the volume of the concrete in the wall is 140 m3.
Step-by-step explanation:
The structure presented in the figure represents a trapezium.
The parallel sides of the trapezium are 1.9 m and 90 cm (i.e., 0.9 m), while the height of the structure is 5m
The area of the trapezium = ½ (sum of the parallel sides) x height
= ½ (1.9 + 0.9) x5
= ½ * 14 = 7 sq m
The area of the structure is 7 m2
The volume of concrete required to build the structure = Area x length of the structure
= 7 x 20
= 140 cubic m
Thus, 140 m3 of concrete is needed for building the wall
Answer:
7m^2 and 140m^3
Step-by-step explanation:
The figure represents a trapezium
The parallel sides are 1.9m and 90 cm( 1m=100cm,0.9m)
while the height is 5m
The area of trapezium=1/2×(sum of parallel sides) ×height
=1/2(1.9+0.9)×5
=1/2×14
=7m^2
The area of the structure =7m^2
Volume of concrete required to build the structure=Area×length kf the structure
=7×20
=140m^3
Therefore,140m^3 of concrete is needed for building the wall.