Adobe of a building is in the form of a hemisphere from inside it was White washed at the cost of rupees 498 9.60 if the cost of whitewashing is rupees 20 per square metre find the inside surface area of the Dome and volume of air inside the Dome
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Answer:
Step-by-step explanation:
Given,
Rate of white washing =20/m^2
Total cost of whote washing=4989.60
Now,
The inside surface area=Total cost/rate
So,
Surface area =4989.60/20
=249.48m^2
Now,
We know that the surface area of hemisphere =4×pie×r^2
So,
249.48m^2= 2× 22/7×r
= 249.48×7/44=r
=r=39.69
Now,
The volume of air that is present in thr dome = 2/3 ×pie×r^3
=131001
monanik05:
Bro
Aapne formula pehle galat likha tha
And ans bhi galat hai
Oo h soory mai abhi thik karta hu
Ab ye sahi to nahi kiya ja sakta lekin ab aaap ko pata chal gaya h ki kaha pe galat to aap galati sudhar lo plz
Mai step 5 se bana kar bhej raha hu comment me hi
Now,
We know that the curved surface area of hemisphere =2×pie×r^2 so,the surface area of given hemisphere =2×22/7×r^2 =249.48=44/7×r^2 =r^2=39.69 =r=6.3 now,you know that the volume of hemisphere is 2/3×pie×r^3 so,the volume of given hemisphere =2/3×22/7×6.3^3 = =523.908
Thanku
But meri exam ho gai
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