Question

Adrian Beltre hit 48 home runs during the 2004 major league baseball season, but only hit 19 home runs in 2005 season. By what percent did Beltre's home run production decrease from 2004 to 2005?

Answer 1

Step-by-step explanation:

difference = 48-19

= 29

production decrease = 29 × 100/ 48

= 60.41%

Answer 2

Given:

Adrian Beltre hit 48 home runs during the 2004 major league baseball season but only hit 19 home runs in the 2005 season.

To find:

The percent by which Beltre's home run production decreased from 2004 to 2005.

Solution:

As given, we have,

In the 2004 major league baseball season, the Adrian Beltre hit home runs = 48

In the 2005 major league baseball season, the Adrian Beltre hit home runs = 19

The decrease in the home runs hit by Adrian Beltre from 2004 to 2005

$= 48 - 19$

$= 29$

Now,

the percentage decrease in Beltre's home run production from 2004 to 2005

$= \frac{decrease\: in \:the\: home\: runs\: from\: 2004 \:to \:2005}{home\: runs\: in \:2004} \times 100$

$= \frac{29}{48} \times 100$

$= 0.60 \times 100$

$= 60\%$

Hence, the percent by which Beltre's home run production decreased from 2004 to 2005 is 60%.