Question

advocate in the form of a frustum of a cone of height 30 cm with radii of radius of its lower and upper ends as 10 cm and 20 CM respectively find the capacity of the bucket also find the cost of milk which can completely filled the bucket as the rate of rupees 40 per litre use pie =22/7
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Answer 1

Answer:

22000

Step-by-step explanation:

volume=1/3*pie*h*(r^2+r*R+R^2)

=

$\frac{1}{3} \times \frac{22}{7} \times 30 \times ( {10}^{2} + 10 \times 20 + {20}^{2} )$

=

$\frac{220}{7} \times (100 + 200 + 400)$

=

$\frac{220}{7} \times 700$

=

$220 \times 100$

=

$22000$

now

volume=22000cm^3

=(22000/1000)l

=22l

cost=volume*rate

=22*40

=Rs.880